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-3y^2+13y+4=0
a = -3; b = 13; c = +4;
Δ = b2-4ac
Δ = 132-4·(-3)·4
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{217}}{2*-3}=\frac{-13-\sqrt{217}}{-6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{217}}{2*-3}=\frac{-13+\sqrt{217}}{-6} $
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